1. Color blindness is a sex-linked trait in humans. A normal woman whose father was color-blind marries a normal man. What will be the proportion of color-blind children?
2. A blue-eyed woman whose father was colorblind marries a normal brown-eyed man whose mother was blue-eyed. What proportion of sons would be blue-eyed and color blind?
3. In cats the genotype BB is black. Bb is tortoise shell, and bb is yellow. The gene is on the X-chromosome. A tortoise shell female is crossed with a black male. What offspring will be expected?
Sex-linked traits?
1)
N=normal n=colour blindness
woman = XN Xn (one from mother-N and one from colourblind father-n)
man= XN Y
possible gametes (sex cells) =
man- 1/2 Y 1/2 XN
woman- 1/2 XN 1/2 Xn
Punnet Square:
.....................XN..........Y
XN...........XN.XN.....XN.Y
Xn............XN.Xn......Xn.Y
children= 1/4 XN XN, 1/4 XN Xn, 1/4 Xn Y, 1/4 XN Y
1/4 chance of having child with colourblindness
(the boy is colourblind as he has the genotype: Xn Y)
3)
BB=black Bb=tortoise shell bb=yellow
tortoise shell female= XB Xb
black male= XB Y
possible gametes (sex cells)
female= 1/2 XB 1/2 Xb
male= 1/2 XB 1/2 Y
punnet square:
...................XB..............Y
XB............XB XB......XB Y
Xb............XB Xb.......Xb Y
children: 1/4 XB XB, 1/4 XB Xb, 1/4 XB Y, 1/4 Xb Y
1/4 black girl, 1/4 tortoise shell girl, 1/4 black boy, 1/4 yellow boy
Reply:you should do your own homework
Reply:1 Xx colorblind gene 50% of the boys 0% of the girls 25% total
2
xx recessive blue woman
Xx colorblind gene
Xx heterozygous brown male
100% blue * 50% blue = 50% blue
males are still 50% colorblind since the x only comes from the mother
so .50*.50 = .25 so 25%
3
males only get 1 x so they can't be tortoise shell.
so its Bb X b
so bb, Bb, B, and b
so 25% yellow females 25% tortoise shell females, 25% black males and 25% yellow males
Reply:100% blue * 50% blue = 50% blue
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