In humans, color vision is X-linked' the gene for color vision is located on the X chromosome but is absent from the Y chromosome. Normal color vision (XN) is dominant over color blindness (Xn). A color blind man fathers the children of a woman with the genotype XNXN
What genotype is the father?
What proportion of daughters will be color-blind?
What proportion of sons will be color blind?
Now one of these daughters marries a color-blind man.
What are the chances that their sons will be color blind?
Explain how a color blind daugher might result from this
couple?
Monohybrid Sex-linked?
The father is Xn Y0 (Y is anything since it doesn't carry the color blind gene.
Do a punett square of father and mother
______ XN | XN
Xn | XNXn | XNXn
Y0 | XNY0 | XNY0
None of the children daughters or sons will be colorblind.
Daughter genotype XNXn (she's a carrier of color blindness)
Blind man genotype XnY0
another punett square
____ XN | Xn
Xn | XNXn | XnXn
Y0 | XNY0 | XnY0
half the sons will be color blind.
A color blind daughter would occur if the carrier gene from the mother happened to be passed on. Since the only X chromosome the father has contains the color blind gene she woul get two Xn chromosomes resulting in color blindness.
Hope this has helped
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